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10. A car of mass 1500kg tows a trailer of mass 2500kg. The driving force of the road on the wheels of the car is 7000N and both the car and the trailer experience resistive forces of 1000N.The acceleration of the vehicle is:

Question

  1. A car of mass 1500kg tows a trailer of mass 2500kg. The driving force of the road on the wheels of the car is 7000N and both the car and the trailer experience resistive forces of 1000N.The acceleration of the vehicle is:
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Solution

To solve this problem, we need to use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The formula is F = ma, where F is the net force, m is the mass, and a is the acceleration.

Step 1: Calculate the total mass of the car and the trailer. The total mass (m) = mass of the car + mass of the trailer = 1500 kg + 2500 kg = 4000 kg.

Step 2: Calculate the total force acting on the vehicle. The total force (F) = driving force - resistive forces = 7000 N - 2*1000 N = 5000 N. We multiply the resistive force by 2 because both the car and the trailer experience this force.

Step 3: Substitute the values into the formula and solve for acceleration (a). So, 5000 N = 4000 kg * a => a = 5000 N / 4000 kg = 1.25 m/s².

Therefore, the acceleration of the vehicle is 1.25 m/s².

This problem has been solved

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