#include <stdio.h>#include<stdlib.h>int main(){ int n; scanf("%d",&n); int a[n]; for(int i=0;i<n;i++){ scanf("%d",&a[i]); } int m=n/2;… printf("%d",a[j]); } for(int k=m;k<n;k++){ printf("%d",a[k]); } } }
Question
#include <stdio.h>#include<stdlib.h>int main(){ int n; scanf("%d",&n); int a[n]; for(int i=0;i<n;i++){ scanf("%d",&a[i]); } int m=n/2;… printf("%d",a[j]); } for(int k=m;k<n;k++){ printf("%d",a[k]); } } }
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Solution
The given code appears to be written in C programming language. It includes the standard input/output library (stdio.h) and the standard library (stdlib.h).
The main function is defined, which is the entry point of the program. Inside the main function, the following steps are performed:
- A variable 'n' is declared to store the size of the array.
- The value of 'n' is taken as input from the user using the scanf function.
- An array 'a' of size 'n' is declared.
- A loop is used to iterate 'n' times to take input for each element of the array using the scanf function.
- A variable 'm' is declared and assigned the value of 'n/2', which represents the middle index of the array.
- A loop is used to print the elements of the array from index 0 to 'm-1'.
- Another loop is used to print the elements of the array from index 'm' to 'n-1'.
- The main function ends.
Please note that the code snippet provided is incomplete and there might be some missing code or syntax errors.
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