Sure, here is a Python program that calculates the Hailstone sequence:

```python
def hailstone(n):
sequence = [n]
while n != 1:
if n % 2 == 0:
n = n // 2
else:
n = 3 * n + 1
sequence.append(n)
return sequence

n = int(input("Enter a number: "))
sequence = hailstone(n)

print(" ".join(str(i) for i in sequence))
print("The length of the sequence is {}.".format(len(sequence)))
```

This program defines a function `hailstone` that takes an integer `n` as input and generates the Hailstone sequence starting from `n`. The sequence is stored in a list. The function uses a while loop to generate the sequence: if `n` is even, it is divided by 2; if `n` is odd, it is multiplied by 3 and 1 is added. The new value of `n` is appended to the list. The loop continues until `n` is 1.

The program then asks the user to input a number, generates the Hailstone sequence for that number, and prints the sequence and its length.

Question

Sure, here is a Python program that calculates the Hailstone sequence:

```python
def hailstone(n):
    sequence = [n]
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            n = 3 * n + 1
        sequence.append(n)
    return sequence

n = int(input("Enter a number: "))
sequence = hailstone(n)

print(" ".join(str(i) for i in sequence))
print("The length of the sequence is {}.".format(len(sequence)))
```

This program defines a function `hailstone` that takes an integer `n` as input and generates the Hailstone sequence starting from `n`. The sequence is stored in a list. The function uses a while loop to generate the sequence: if `n` is even, it is divided by 2; if `n` is odd, it is multiplied by 3 and 1 is added. The new value of `n` is appended to the list. The loop continues until `n` is 1.

The program then asks the user to input a number, generates the Hailstone sequence for that number, and prints the sequence and its length.

Knowee AI · Accepted Answer

Sure, here is a Python program that calculates the Hailstone sequence:

```python
def hailstone(n):
    sequence = [n]
    while n != 1:
        if n % 2 == 0:
            n = n // 2
        else:
            n = 3 * n + 1
        sequence.append(n)
    return sequence

n = int(input("Enter a number: "))
sequence = hailstone(n)

print(" ".join(str(i) for i in sequence))
print("The length of the sequence is {}.".format(len(sequence)))
```

This program defines a function `hailstone` that takes an integer `n` as input and generates the Hailstone sequence starting from `n`. The sequence is stored in a list. The function uses a while loop to generate the sequence: if `n` is even, it is divided by 2; if `n` is odd, it is multiplied by 3 and 1 is added. The new value of `n` is appended to the list. The loop continues until `n` is 1.

The program then asks the user to input a number, generates the Hailstone sequence for that number, and prints the sequence and its length.

Question

Solution

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