nswerWhat will be the output of the python code shown below for various styles of format specifiers?>>>x = 1234>>>res = 'integers:...%d...%-6d...%06d' %(x, x, x)>>>res
Question
nswerWhat will be the output of the python code shown below for various styles of format specifiers?>>>x = 1234>>>res = 'integers:...%d...%-6d...%06d' %(x, x, x)>>>res
Solution
The output of the Python code will be:
'integers:...1234...1234 ...001234'
Here's the step by step explanation:
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%d: This is a placeholder for an integer. The value of 'x' (which is 1234) will replace %d.
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%-6d: This is also a placeholder for an integer. The '-' sign indicates left alignment. '6' is the width of the field. So, the integer value '1234' will be left-aligned within a field of width 6. This will add two spaces after the number because the number 1234 is 4 digits, so 6-4 = 2 spaces.
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%06d: This is another placeholder for an integer. The '0' indicates that the empty spaces should be filled with zeros. '6' is the width of the field. So, the integer value '1234' will be right-aligned within a field of width 6, and the empty spaces will be filled with zeros. This will add two zeros before the number because the number 1234 is 4 digits, so 6-4 = 2 zeros.
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