A single-acting triplex pump of an output power of 1,250 hp is used to deliver the required rate at running speed of 110 strokes/min. The liner size and length are 5.5 and 30 inches, respectively. If the displacement efficiency is 90%, calculate the discharge pressure of the pump at that speed.
Question
A single-acting triplex pump of an output power of 1,250 hp is used to deliver the required rate at running speed of 110 strokes/min. The liner size and length are 5.5 and 30 inches, respectively. If the displacement efficiency is 90%, calculate the discharge pressure of the pump at that speed.
Solution
To calculate the discharge pressure of the pump, we need to use the following formula:
P = (HP * 42.4) / (Q * η)
Where:
- P is the discharge pressure
- HP is the horsepower, which is 1250 in this case
- Q is the flow rate, which can be calculated using the formula Q = (A * L * N) / 231, where A is the area of the liner, L is the length of the liner, and N is the number of strokes per minute
- η is the efficiency, which is 90% or 0.9 in this case
First, we need to calculate the area of the liner. The area of a circle is given by the formula A = πr², where r is the radius. The diameter of the liner is 5.5 inches, so the radius is 5.5 / 2 = 2.75 inches. Therefore, the area of the liner is A = π * (2.75)² = 23.76 square inches.
Next, we calculate the flow rate. Using the formula Q = (A * L * N) / 231, we get Q = (23.76 * 30 * 110) / 231 = 373.6 gallons per minute.
Finally, we can calculate the discharge pressure. Using the formula P = (HP * 42.4) / (Q * η), we get P = (1250 * 42.4) / (373.6 * 0.9) = 1500 psi.
Therefore, the discharge pressure of the pump at that speed is 1500 psi.
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