To solve this problem, we need to use the concept of inverse variation. When two quantities vary inversely, their product is constant. Let's denote the number of people attending by $ n $ and the cost per person by $ C $. According to the problem, $ n \times C = k $, where $ k $ is a constant.

Given:
- When 90 people attended, the cost was $50 per person.

First, we find the constant $ k $:
$$ k = n \times C $$
$$ k = 90 \times 50 $$
$$ k = 4500 $$

Now, we need to find the number of people ($ n $) required for the cost to be $30 per person. Using the constant $ k $:
$$ k = n \times 30 $$
$$ 4500 = n \times 30 $$

Solving for $ n $:
$$ n = \frac{4500}{30} $$
$$ n = 150 $$

Therefore, 150 people need to attend for the cost to be $30 per person.

Question

To solve this problem, we need to use the concept of inverse variation. When two quantities vary inversely, their product is constant. Let's denote the number of people attending by $ n $ and the cost per person by $ C $. According to the problem, $ n \times C = k $, where $ k $ is a constant.

Given:
- When 90 people attended, the cost was $50 per person.

First, we find the constant $ k $:
$$ k = n \times C $$
$$ k = 90 \times 50 $$
$$ k = 4500 $$

Now, we need to find the number of people ($ n $) required for the cost to be $30 per person. Using the constant $ k $:
$$ k = n \times 30 $$
$$ 4500 = n \times 30 $$

Solving for $ n $:
$$ n = \frac{4500}{30} $$
$$ n = 150 $$

Therefore, 150 people need to attend for the cost to be $30 per person.

Knowee AI · Accepted Answer

To solve this problem, we need to use the concept of inverse variation. When two quantities vary inversely, their product is constant. Let's denote the number of people attending by $ n $ and the cost per person by $ C $. According to the problem, $ n \times C = k $, where $ k $ is a constant.

Given:
- When 90 people attended, the cost was $50 per person.

First, we find the constant $ k $:
$$ k = n \times C $$
$$ k = 90 \times 50 $$
$$ k = 4500 $$

Now, we need to find the number of people ($ n $) required for the cost to be $30 per person. Using the constant $ k $:
$$ k = n \times 30 $$
$$ 4500 = n \times 30 $$

Solving for $ n $:
$$ n = \frac{4500}{30} $$
$$ n = 150 $$

Therefore, 150 people need to attend for the cost to be $30 per person.

The cost per person for a school formal varies inversely with the number of people attending. When 90 people attended, the cost was $50 per person.How many people need to attend for the cost to be $30 per person?

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