If ε0 and μ0 are the electric permittivity and magnetic permeability in vacuum, ε and μ are corresponding quantities in medium, then refractive index of the medium isεε0−−√ε0μεμ0−−−√ε0μ0εμ−−−√εμε0μ0−−−√
Question
If ε0 and μ0 are the electric permittivity and magnetic permeability in vacuum, ε and μ are corresponding quantities in medium, then refractive index of the medium isεε0−−√ε0μεμ0−−−√ε0μ0εμ−−−√εμε0μ0−−−√
Solution
The refractive index of a medium is given by the square root of the ratio of permittivity and permeability of the medium to that of vacuum. This can be mathematically represented as:
n = √((ε/ε0) * (μ/μ0))
Where: n is the refractive index, ε is the permittivity of the medium, ε0 is the permittivity of vacuum, μ is the permeability of the medium, and μ0 is the permeability of vacuum.
However, in most cases, the permeability of the medium (μ) is approximately equal to the permeability of vacuum (μ0), especially for non-magnetic materials. Therefore, the equation simplifies to:
n = √(ε/ε0)
This equation tells us that the refractive index of a medium is directly related to its permittivity. The higher the permittivity of the medium compared to vacuum, the higher its refractive index.
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