What does the following program print?#include <stdio.h>int main() {    int arr[5] = {1, 2, 3, 4, 5};    int *p = arr;    p++;    printf("%d\n", *p);    return 0;}

The program prints "2".

Here's the step-by-step explanation:

1. An array arr of 5 integers is declared and initialized with the values 1, 2, 3, 4, 5.

2. A pointer p is declared and initialized to point to the first element of the array arr.

3. The pointer p is incremented by 1. This means that p now points to the second element of the array arr.

4. The value of the element pointed to by p is printed. Since p is pointing to the second element of the array, the value "2" is printed.

5. The program returns 0, indicating successful execution.