A 0.52 kilogram rocket is launched by an engine that exerts an average force of 8.00 N. What is the rocket's acceleration in m/s2 correct to one decimal place

To find the acceleration, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass. The formula is:

a = F/m

where: a is the acceleration, F is the force, and m is the mass.

Given in the problem: F = 8.00 N (Newtons) and m = 0.52 kg (kilograms)

Substituting these values into the formula, we get:

a = 8.00 N / 0.52 kg = 15.38 m/s²

Rounding to one decimal place, the rocket's acceleration is 15.4 m/s².

To find the acceleration, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass. The formula is:

a = F/m

where: a is the acceleration, F is the force, and m is the mass of the object.

Given: F = 8.00 N (force) m = 0.52 kg (mass)

Substitute the given values into the formula:

a = 8.00 N / 0.52 kg = 15.38 m/s²

So, the acceleration of the rocket is 15.4 m/s² to one decimal place.