Sure, here is a step by step solution in Python:

1. First, define the two arrays. For example:
```python
arr1 = [10, 20, 30, 40, 50]
arr2 = [60, 70, 80, 90, 100]
```
2. Convert the second array to a set for faster lookup:
```python
arr2_set = set(arr2)
```
3. Sort the first array in descending order:
```python
arr1.sort(reverse=True)
```
4. Iterate over the sorted array and return the first number that is not in the second array:
```python
for num in arr1:
if num not in arr2_set:
print(num)
break
```
5. If no such number is found, print 0:
```python
else:
print(0)
```
The complete code would look like this:
```python
arr1 = [10, 20, 30, 40, 50]
arr2 = [60, 70, 80, 90, 100]

arr2_set = set(arr2)
arr1.sort(reverse=True)

for num in arr1:
if num not in arr2_set:
print(num)
break
else:
print(0)
```
This code will print the largest number in arr1 that is not present in arr2, or 0 if no such number exists.

Question

Sure, here is a step by step solution in Python:

1. First, define the two arrays. For example:
```python
arr1 = [10, 20, 30, 40, 50]
arr2 = [60, 70, 80, 90, 100]
```
2. Convert the second array to a set for faster lookup:
```python
arr2_set = set(arr2)
```
3. Sort the first array in descending order:
```python
arr1.sort(reverse=True)
```
4. Iterate over the sorted array and return the first number that is not in the second array:
```python
for num in arr1:
    if num not in arr2_set:
        print(num)
        break
```
5. If no such number is found, print 0:
```python
else:
    print(0)
```
The complete code would look like this:
```python
arr1 = [10, 20, 30, 40, 50]
arr2 = [60, 70, 80, 90, 100]

arr2_set = set(arr2)
arr1.sort(reverse=True)

for num in arr1:
    if num not in arr2_set:
        print(num)
        break
else:
    print(0)
```
This code will print the largest number in arr1 that is not present in arr2, or 0 if no such number exists.

Knowee AI · Accepted Answer

Sure, here is a step by step solution in Python:

1. First, define the two arrays. For example:
```python
arr1 = [10, 20, 30, 40, 50]
arr2 = [60, 70, 80, 90, 100]
```
2. Convert the second array to a set for faster lookup:
```python
arr2_set = set(arr2)
```
3. Sort the first array in descending order:
```python
arr1.sort(reverse=True)
```
4. Iterate over the sorted array and return the first number that is not in the second array:
```python
for num in arr1:
    if num not in arr2_set:
        print(num)
        break
```
5. If no such number is found, print 0:
```python
else:
    print(0)
```
The complete code would look like this:
```python
arr1 = [10, 20, 30, 40, 50]
arr2 = [60, 70, 80, 90, 100]

arr2_set = set(arr2)
arr1.sort(reverse=True)

for num in arr1:
    if num not in arr2_set:
        print(num)
        break
else:
    print(0)
```
This code will print the largest number in arr1 that is not present in arr2, or 0 if no such number exists.

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