Pa = 20 kN; Pb = 10 kN; α = 75°Solve for the resultant P (kN).QUESTION 5ANSWERA.10.15B.22.59C.24.57D.9.96
Question
Pa = 20 kN; Pb = 10 kN; α = 75°Solve for the resultant P (kN).QUESTION 5ANSWERA.10.15B.22.59C.24.57D.9.96
Solution
The problem seems to be about calculating the resultant of two forces. Here are the steps to solve it:
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Convert the angles into radians if they are given in degrees. In this case, α = 75° = 75*(π/180) = 1.309 radians.
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The resultant force P can be found using the formula: P = sqrt(Pa^2 + Pb^2 + 2PaPb*cos(α)).
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Substitute the given values into the formula: P = sqrt((20)^2 + (10)^2 + 22010*cos(1.309)).
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Calculate the value inside the square root: P = sqrt(400 + 100 + 2200cos(1.309)).
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Calculate the value of cos(1.309) and multiply it by 400: P = sqrt(500 + 400*cos(1.309)).
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Add the results: P = sqrt(500 + 400*-0.2588).
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Calculate the square root: P = sqrt(500 - 103.52).
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Finally, calculate the resultant force P: P = sqrt(396.48) = 19.91 kN.
So, none of the options A, B, C, D are correct. The resultant force P is approximately 19.91 kN.
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