To solve this problem, we first need to understand the total possible outcomes when two dice are thrown. Since a die has 6 faces, the total possible outcomes are 6*6 = 36.

Next, we need to find the outcomes where the sum of the two dice is even. The pairs that satisfy this condition are (1,1), (1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,2), (4,4), (4,6), (5,1), (5,3), (5,5), (6,2), (6,4), (6,6). So, there are 18 such pairs.

Now, we need to find the outcomes where one of the dice is 2. Among the 18 pairs we found, the pairs that satisfy this condition are (2,2), (2,4), (2,6), (1,2), (3,2), (4,2), (5,2), (6,2). So, there are 8 such pairs.

Therefore, the probability that one of the die is 2 given that the sum of the two dice is even is 8/18 = 4/9. However, this option is not given in the question. It seems there might be a mistake in the question or the given options.

Question

To solve this problem, we first need to understand the total possible outcomes when two dice are thrown. Since a die has 6 faces, the total possible outcomes are 6*6 = 36.

Next, we need to find the outcomes where the sum of the two dice is even. The pairs that satisfy this condition are (1,1), (1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,2), (4,4), (4,6), (5,1), (5,3), (5,5), (6,2), (6,4), (6,6). So, there are 18 such pairs.

Now, we need to find the outcomes where one of the dice is 2. Among the 18 pairs we found, the pairs that satisfy this condition are (2,2), (2,4), (2,6), (1,2), (3,2), (4,2), (5,2), (6,2). So, there are 8 such pairs.

Therefore, the probability that one of the die is 2 given that the sum of the two dice is even is 8/18 = 4/9. However, this option is not given in the question. It seems there might be a mistake in the question or the given options.

Knowee AI · Accepted Answer

To solve this problem, we first need to understand the total possible outcomes when two dice are thrown. Since a die has 6 faces, the total possible outcomes are 6*6 = 36.

Next, we need to find the outcomes where the sum of the two dice is even. The pairs that satisfy this condition are (1,1), (1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,2), (4,4), (4,6), (5,1), (5,3), (5,5), (6,2), (6,4), (6,6). So, there are 18 such pairs.

Now, we need to find the outcomes where one of the dice is 2. Among the 18 pairs we found, the pairs that satisfy this condition are (2,2), (2,4), (2,6), (1,2), (3,2), (4,2), (5,2), (6,2). So, there are 8 such pairs.

Therefore, the probability that one of the die is 2 given that the sum of the two dice is even is 8/18 = 4/9. However, this option is not given in the question. It seems there might be a mistake in the question or the given options.

Let two dice be thrown together. Find the probability that one of the die is 2 if the sum of the two dice is even. 2/7 5/6 1/6 3/7

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