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The soldiers in two armies when they met in a battle were in the ratio of 10 : 3. Their respective losses were as 20 : 3 and the survivors as 40 : 13. If the number of survivors in the larger army be 24,000, find the original number of soldiers in each army ?28000, 840025000, 750029000, 275026000, 7800

Question

The soldiers in two armies when they met in a battle were in the ratio of 10 : 3. Their respective losses were as 20 : 3 and the survivors as 40 : 13. If the number of survivors in the larger army be 24,000, find the original number of soldiers in each army ?28000, 840025000, 750029000, 275026000, 7800

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Solution

Let's denote the number of soldiers in the larger army as 10x and in the smaller army as 3x.

According to the problem, the ratio of survivors in the larger army to the smaller army is 40:13. We also know that the number of survivors in the larger army is 24,000.

So, we can set up the following proportion to find the value of x:

40/13 = 24,000/x

Solving for x gives us x = 7,800.

Therefore, the original number of soldiers in the larger army was 10x = 107,800 = 78,000 and in the smaller army was 3x = 37,800 = 23,400.

So, the answer is 78,000 and 23,400.

This problem has been solved

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