The average of eight numbers is 104. The average of six of these numbers is 116. Then the greater number of the two numbers is:

To solve this problem, we first need to find the total sum of the eight numbers and the total sum of the six numbers.

Step 1: The average of eight numbers is 104, so the total sum of these eight numbers is 8 * 104 = 832.

Step 2: The average of six of these numbers is 116, so the total sum of these six numbers is 6 * 116 = 696.

Step 3: Now, we subtract the total sum of the six numbers from the total sum of the eight numbers to find the sum of the two remaining numbers. So, 832 - 696 = 136. This means that the sum of the two remaining numbers is 136.

Step 4: Since we don't know the individual values of these two numbers, we can't definitively say which one is greater. However, we do know that neither of these numbers can be greater than 136 (since that's their total sum). So, the greater of the two numbers is less than or equal to 136.