If glucose-6-phosphate is used for NADPH synthesis more than for NADH synthesis inside a cell, which of the following metabolic processes is most active in the cell?A.Reduction of glucose metabolites in the cytosol to produce ATPB.Reduction of antioxidant NADP+ moleculesC.Production of five-carbon sugar phosphates in the cytosolD.Oxidation of glucose metabolites inside mitochondria to produce CO2Submit
Question
If glucose-6-phosphate is used for NADPH synthesis more than for NADH synthesis inside a cell, which of the following metabolic processes is most active in the cell?A.Reduction of glucose metabolites in the cytosol to produce ATPB.Reduction of antioxidant NADP+ moleculesC.Production of five-carbon sugar phosphates in the cytosolD.Oxidation of glucose metabolites inside mitochondria to produce CO2Submit
Solution
The answer is B. Reduction of antioxidant NADP+ molecules.
Here's why:
Glucose-6-phosphate can be used in different metabolic pathways, including glycolysis (which produces NADH) and the pentose phosphate pathway (which produces NADPH).
If glucose-6-phosphate is being used more for NADPH synthesis than for NADH synthesis, this suggests that the pentose phosphate pathway is more active in the cell.
One of the main functions of the pentose phosphate pathway is to produce NADPH, which is used in reductive biosynthesis reactions within cells (such as fatty acid synthesis) and in the reduction of antioxidant NADP+ molecules.
Therefore, if NADPH synthesis is high, it suggests that the cell is actively reducing antioxidant NADP+ molecules. Hence, the answer is B. Reduction of antioxidant NADP+ molecules.
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