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What does the following Python code snippet do?class LinkedList:    def __init__(self):        self.head = None    def append(self, data):        new_node = Node(data)        if self.head is None:            self.head = new_node        else:            current = self.head            while current.next:                current = current.next            current.next = new_node

Question

What does the following Python code snippet do?class LinkedList:    def init(self):        self.head = None    def append(self, data):        new_node = Node(data)        if self.head is None:            self.head = new_node        else:            current = self.head            while current.next:                current = current.next            current.next = new_node

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Solution

This Python code defines a simple implementation of a linked list data structure.

  1. The LinkedList class is defined with two methods: __init__ and append.

  2. The __init__ method is the constructor that is automatically called when an object of the LinkedList class is created. It initializes the head of the linked list to None, indicating that the list is initially empty.

  3. The append method is used to add a new element to the end of the linked list. It takes data as a parameter, which is the data to be stored in the new node.

  4. In the append method, a new node is created with the given data using new_node = Node(data).

  5. If the linked list is empty (i.e., self.head is None), the new node is set as the head of the list.

  6. If the linked list is not empty, the method traverses the list to find the last node (i.e., the node where current.next is None). It does this using a while loop.

  7. Once the last node is found, the new node is added after the last node by setting current.next = new_node.

Please note that the Node class is not defined in this snippet. Typically, a Node class for a linked list would look something like this:

class Node:
    def __init__(self, data=None):
        self.data = data
        self.next = None

This class has a constructor that sets the data attribute to the provided value and the next attribute to None. The next attribute is used to point to the next node in the linked list.

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Similar Questions

What will be the output of the following code?class Node:  def __init__(self, data=None):    self.data = data    self.next = Noneclass LinkedList:  def __init__(self):    self.head = None  def print_list(self):    current_node = self.head    while current_node:      print(current_node.data)      current_node = current_node.next  def insert_at_end(self, new_data):    new_node = Node(new_data)    if self.head is None:      self.head = new_node      return    last_node = self.head    while last_node.next:      last_node = last_node.next    last_node.next = new_nodellist = LinkedList()llist.insert_at_end(1)llist.insert_at_end(2)llist.insert_at_end(3)llist.print_list()Options321132123213

What does the following Python code snippet accomplish?def reverse_linked_list(head):    prev = None    current = head    while current is not None:        next_node = current.next        current.next = prev        prev = current        current = next_node    head = prev    return head

What does the following Python code snippet accomplish?class Node:    def __init__(self, data):        self.data = data        self.next = Nonenode1 = Node(1)node2 = Node(2)node1.next = node2Creates two linked list nodes with data 1 and 2, respectivelyCreates a singly linked list with two nodes containing data 1 and 2, respectivelyCreates a doubly linked list with two nodes containing data 1 and 2, respectivelyRaises a syntax error

What is the purpose of the append method in a linked list?Inserts a new node at the beginning of the linked listDeletes the last node of the linked listAppends a new node to the end of the linked listReverses the linked list

What does the following Python code snippet do?def delete_node(self, key):    temp = self.head    if temp is not None:        if temp.data == key:            self.head = temp.next            temp = None            return    while temp is not None:        if temp.data == key:            break        prev = temp        temp = temp.next    if temp == None:        return    prev.next = temp.next    temp = None

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