To solve this problem, we need to consider the number of digits in the numbers between 200000 and 600000, which is 6 digits.

1. For the first digit, we have 4 choices (2, 3, 4, 5). We can't use 0, 1, or 6 because the number would be less than 200000 or more than 600000.

2. For the remaining 5 digits, we have 7 choices each (0, 1, 2, 3, 4, 5, 6) because repetition is allowed.

So, the total number of numbers that can be formed is 4 (choices for the first digit) * 7^5 (choices for the remaining 5 digits) = 67228.

So, the correct answer is b. 67228.

Question

To solve this problem, we need to consider the number of digits in the numbers between 200000 and 600000, which is 6 digits.

1. For the first digit, we have 4 choices (2, 3, 4, 5). We can't use 0, 1, or 6 because the number would be less than 200000 or more than 600000.

2. For the remaining 5 digits, we have 7 choices each (0, 1, 2, 3, 4, 5, 6) because repetition is allowed.

So, the total number of numbers that can be formed is 4 (choices for the first digit) * 7^5 (choices for the remaining 5 digits) = 67228.

So, the correct answer is b. 67228.

Knowee AI · Accepted Answer

To solve this problem, we need to consider the number of digits in the numbers between 200000 and 600000, which is 6 digits.

1. For the first digit, we have 4 choices (2, 3, 4, 5). We can't use 0, 1, or 6 because the number would be less than 200000 or more than 600000.

2. For the remaining 5 digits, we have 7 choices each (0, 1, 2, 3, 4, 5, 6) because repetition is allowed.

So, the total number of numbers that can be formed is 4 (choices for the first digit) * 7^5 (choices for the remaining 5 digits) = 67228.

So, the correct answer is b. 67228.

How many numbers between 200000 and 600000 can be formed using the digits {0,1, 2, 3, 4,5, and 6} where repetition is allowed?Question 15Answera.67337b.67228c.77227d.68227