To create a stem plot, we first need to separate the stem (tens place) from the leaf (ones place) for each number. Here's how it would look:

Stem | Leaf
--- | ---
2 | 1, 7
3 | 0, 2, 2, 2, 3, 5, 5, 8, 9, 9, 9
4 | 0, 1, 2, 3, 4, 6
5 | 0, 0, 4, 4, 7, 7

To identify any outliers, we first need to calculate the interquartile range (IQR). The IQR is the range within which the central 50% of the data falls.

First, we need to find the first quartile (Q1) and the third quartile (Q3). Q1 is the median of the first half of the data and Q3 is the median of the second half of the data.

For this data set, Q1 is 32 and Q3 is 50.

The IQR is Q3 - Q1, which is 50 - 32 = 18.

Any data point that falls below Q1 - 1.5*IQR or above Q3 + 1.5*IQR is considered an outlier.

Q1 - 1.5*IQR = 32 - 1.5*18 = -5
Q3 + 1.5*IQR = 50 + 1.5*18 = 87

Since all the data points fall within this range, there are no outliers. So, the answer is NONE.

Question

To create a stem plot, we first need to separate the stem (tens place) from the leaf (ones place) for each number. Here's how it would look:

Stem | Leaf
--- | ---
2 | 1, 7
3 | 0, 2, 2, 2, 3, 5, 5, 8, 9, 9, 9
4 | 0, 1, 2, 3, 4, 6
5 | 0, 0, 4, 4, 7, 7

To identify any outliers, we first need to calculate the interquartile range (IQR). The IQR is the range within which the central 50% of the data falls.

First, we need to find the first quartile (Q1) and the third quartile (Q3). Q1 is the median of the first half of the data and Q3 is the median of the second half of the data.

For this data set, Q1 is 32 and Q3 is 50.

The IQR is Q3 - Q1, which is 50 - 32 = 18.

Any data point that falls below Q1 - 1.5*IQR or above Q3 + 1.5*IQR is considered an outlier.

Q1 - 1.5*IQR = 32 - 1.5*18 = -5
Q3 + 1.5*IQR = 50 + 1.5*18 = 87

Since all the data points fall within this range, there are no outliers. So, the answer is NONE.

Knowee AI · Accepted Answer

To create a stem plot, we first need to separate the stem (tens place) from the leaf (ones place) for each number. Here's how it would look:

Stem | Leaf
--- | ---
2 | 1, 7
3 | 0, 2, 2, 2, 3, 5, 5, 8, 9, 9, 9
4 | 0, 1, 2, 3, 4, 6
5 | 0, 0, 4, 4, 7, 7

To identify any outliers, we first need to calculate the interquartile range (IQR). The IQR is the range within which the central 50% of the data falls.

First, we need to find the first quartile (Q1) and the third quartile (Q3). Q1 is the median of the first half of the data and Q3 is the median of the second half of the data.

For this data set, Q1 is 32 and Q3 is 50.

The IQR is Q3 - Q1, which is 50 - 32 = 18.

Any data point that falls below Q1 - 1.5*IQR or above Q3 + 1.5*IQR is considered an outlier.

Q1 - 1.5*IQR = 32 - 1.5*18 = -5
Q3 + 1.5*IQR = 50 + 1.5*18 = 87

Since all the data points fall within this range, there are no outliers. So, the answer is NONE.

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Stem	Leaf
2	1, 7
3	0, 2, 2, 2, 3, 5, 5, 8, 9, 9, 9
4	0, 1, 2, 3, 4, 6
5	0, 0, 4, 4, 7, 7