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What will be the output of the following Python code?s={4>3, 0, 3-3}all(s)any(s)TrueFalse FalseTrue True True FalseFalse

Question

What will be the output of the following Python code?s={4>3, 0, 3-3}all(s)any(s)TrueFalse FalseTrue True True FalseFalse

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Solution

The Python code you provided is not formatted correctly, but I will try to interpret it as best as I can.

It seems like you are creating a set s with three elements: 4>3, 0, and 3-3.

In Python, 4>3 is a boolean expression that evaluates to True, 0 is an integer that is equivalent to False in a boolean context, and 3-3 results in 0, which is also equivalent to False in a boolean context.

So, your set s is equivalent to {True, False, False}.

The all() function in Python returns True if all elements in the iterable (in this case, the set s) are true. Since s contains False values, all(s) will return False.

The any() function in Python returns True if at least one element in the iterable is true. Since s contains a True value, any(s) will return True.

So, the output of your code should be:

False
True

This problem has been solved

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