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Two particles are placed at some distance. If the mass of each of the two particles is doubled keeping the distance between them unchanged, the value of gravitational force between them will be: time4 time timeUnchanged

Question

Two particles are placed at some distance. If the mass of each of the two particles is doubled keeping the distance between them unchanged, the value of gravitational force between them will be: time4 time timeUnchanged

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Solution

The gravitational force between two particles is given by Newton's law of universal gravitation:

F = G * (m1 * m2) / r^2

where:

  • F is the force between the masses,
  • G is the gravitational constant,
  • m1 and m2 are the masses of the particles,
  • r is the distance between the centers of the two particles.

If the mass of each of the two particles is doubled, the equation becomes:

F' = G * (2m1 * 2m2) / r^2 = 4 * G * (m1 * m2) / r^2 = 4F

So, the value of gravitational force between them will be four times the original force.

This problem has been solved

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