Select the correct answerAnalyse the code and choose right option.#include <stdio.h>void FunctionA(void){ static int A; A++; printf("FunctionA:%d\n",A);} void FunctionB(void){ static int A; A++; printf("FunctionB:%d\n",A);} int main(){ FunctionA(), FunctionB(), FunctionA(); return 0;}OptionsCompile time errorFunctionA:1FunctionB:1FunctionA:1FunctionA:1FunctionB:1FunctionA:2FunctionA:0FunctionB:1FunctionA:2FunctionA:1FunctionB:2FunctionA:1FunctionA:2FunctionB:2FunctionA:2

The correct answer is:

FunctionA:1 FunctionB:1 FunctionA:2

Explanation:

The code defines two functions, FunctionA and FunctionB, each with a static integer variable A. A static variable retains its value between function calls.

In the main function, FunctionA is called first, which initializes A to 0 (default value for static variables), increments it by 1, and then prints "FunctionA:1".

Next, FunctionB is called. It has its own static variable A, which is also initialized to 0, incremented by 1, and then "FunctionB:1" is printed.

Finally, FunctionA is called again. This time, it uses the existing value of A (which is 1 from the previous call), increments it by 1, and then prints "FunctionA:2".

So, the output of the program is:

FunctionA:1 FunctionB:1 FunctionA:2