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Which option correctly matches a string that starts with 'a' and ends with 'z', with any number of characters in between?^a*z$a*z^a.*z$a.+z

Question

Which option correctly matches a string that starts with 'a' and ends with 'z', with any number of characters in between?^a*zaza.za*z^a.*za.+z

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Solution

The correct option is ^a.*z$.

Here's why:

  • ^ denotes the start of a line.
  • a is the first character.
  • .* means any character (.) any number of times (*).
  • z is the last character.
  • $ denotes the end of a line.

So, ^a.*z$ will match any string that starts with 'a' and ends with 'z', with any number of characters in between.

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