To find the number of pairs of letters in the word "PANICKING" that have the same number of letters between them as in the English alphabet, we need to follow these steps:

1. Identify the letters in the word "PANICKING": P, A, N, I, C, K, I, N, G.

2. Count the number of letters between each pair of letters in the word. For example, between P and A, there are 1 letter (O); between A and N, there are 1 letter (B); between N and I, there are 1 letter (M); between I and C, there are 2 letters (H, J); between C and K, there are 1 letter (D); between K and I, there are 1 letter (J); between I and N, there are 1 letter (M); between N and G, there are 2 letters (O, P).

3. Compare the number of letters between each pair to the number of letters in the English alphabet (26 letters).

4. Count the pairs that have the same number of letters between them as in the English alphabet. In this case, there are two pairs: (I, C, K) and (N, G).

5. Therefore, the correct answer is Two.

Note: The pairs can be counted in both forward and backward directions, so we consider both directions in this calculation.

Question

To find the number of pairs of letters in the word "PANICKING" that have the same number of letters between them as in the English alphabet, we need to follow these steps:

1. Identify the letters in the word "PANICKING": P, A, N, I, C, K, I, N, G.

2. Count the number of letters between each pair of letters in the word. For example, between P and A, there are 1 letter (O); between A and N, there are 1 letter (B); between N and I, there are 1 letter (M); between I and C, there are 2 letters (H, J); between C and K, there are 1 letter (D); between K and I, there are 1 letter (J); between I and N, there are 1 letter (M); between N and G, there are 2 letters (O, P).

3. Compare the number of letters between each pair to the number of letters in the English alphabet (26 letters).

4. Count the pairs that have the same number of letters between them as in the English alphabet. In this case, there are two pairs: (I, C, K) and (N, G).

5. Therefore, the correct answer is Two.

Note: The pairs can be counted in both forward and backward directions, so we consider both directions in this calculation.

Knowee AI · Accepted Answer

To find the number of pairs of letters in the word "PANICKING" that have the same number of letters between them as in the English alphabet, we need to follow these steps:

1. Identify the letters in the word "PANICKING": P, A, N, I, C, K, I, N, G.

2. Count the number of letters between each pair of letters in the word. For example, between P and A, there are 1 letter (O); between A and N, there are 1 letter (B); between N and I, there are 1 letter (M); between I and C, there are 2 letters (H, J); between C and K, there are 1 letter (D); between K and I, there are 1 letter (J); between I and N, there are 1 letter (M); between N and G, there are 2 letters (O, P).

3. Compare the number of letters between each pair to the number of letters in the English alphabet (26 letters).

4. Count the pairs that have the same number of letters between them as in the English alphabet. In this case, there are two pairs: (I, C, K) and (N, G).

5. Therefore, the correct answer is Two.

Note: The pairs can be counted in both forward and backward directions, so we consider both directions in this calculation.

Select the correct answerHow many such pairs of letters are there in the word PANICKING both in forward and backward directions, each of which has as many letters between them in the word as in english alphabets?OptionsNoneMore than ThreeThreeTwoOne

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