𝑦=cos(𝑥)+𝑥2−7 on the interval [0,𝜋] Find the derivative.𝑦′=

To find the derivative of the function y = cos(x) + x^2 - 7 on the interval [0, π], we need to apply the rules of differentiation to each term separately.

The derivative of cos(x) with respect to x is -sin(x).

The derivative of x^2 with respect to x is 2x.

The derivative of a constant, like -7, is 0.

So, the derivative of the function y = cos(x) + x^2 - 7 is:

y' = -sin(x) + 2x + 0

Simplified, this is:

y' = -sin(x) + 2x