Select the correct answerWhat will be the output of the following Python statements?print(oct(10))print(oct(‘10’))OptionsErroro120o12Erroro120o12Error0o12

The correct answer is "Error0o12".

Here's the step-by-step explanation:

1. The oct() function in Python converts an integer to its octal representation. So, oct(10) will return '0o12'. The '0o' prefix represents that the following number is in octal format.

2. However, oct('10') will cause an error. This is because the oct() function expects an integer as an argument, but here we are passing a string ('10'). Python cannot convert a string to its octal representation using the oct() function, hence it will throw a TypeError.

So, the output of the given Python statements will be an error for the second statement, after successfully executing the first statement. Hence, the correct answer is "Error0o12".

The correct answer is "Error 0o12".

Here's why:

The first statement print(oct(10)) converts the integer 10 into its octal representation, which is '0o12' in Python.

The second statement print(oct('10')) will cause an error because the oct() function in Python doesn't accept string arguments. It only accepts integer arguments. So trying to convert a string '10' into an octal will result in a TypeError.