The maximum and minimum values of the function f(x) = a*sin(x) + b*cos(x) can be found using the formula:

sqrt(a² + b²)

Here, a = 4 and b = 3.

So, the maximum value is sqrt(4² + 3²) = sqrt(16 + 9) = sqrt(25) = 5.

The minimum value is -sqrt(a² + b²) = -5.

So, the maximum and minimum values of 4sinx + 3cosx are 5 and -5 respectively. Therefore, the correct option is (5, -5).

Question

The maximum and minimum values of the function f(x) = a*sin(x) + b*cos(x) can be found using the formula:

sqrt(a² + b²)

Here, a = 4 and b = 3.

So, the maximum value is sqrt(4² + 3²) = sqrt(16 + 9) = sqrt(25) = 5.

The minimum value is -sqrt(a² + b²) = -5.

So, the maximum and minimum values of 4sinx + 3cosx are 5 and -5 respectively. Therefore, the correct option is (5, -5).

Knowee AI · Accepted Answer

The maximum and minimum values of the function f(x) = a*sin(x) + b*cos(x) can be found using the formula:

sqrt(a² + b²)

Here, a = 4 and b = 3.

So, the maximum value is sqrt(4² + 3²) = sqrt(16 + 9) = sqrt(25) = 5.

The minimum value is -sqrt(a² + b²) = -5.

So, the maximum and minimum values of 4sinx + 3cosx are 5 and -5 respectively. Therefore, the correct option is (5, -5).

Maximum and minimum value of 4sinx + 3cosx will be -(2, –1)(3, –2)(4, –3)(5, –5)