Problem StatementWrite a query to retrieve the seller ID(s) who made the highest total sales based on the total sum of prices for all their sales.Table: Productproduct_id is the primary key of this table. Each row of this table indicates the name and the price of each product. Table: SalesThis table has no primary key, it can have repeated rows. product_id is a foreign key to the Product table. Note: All records are prepopulated.Input format :The input tables are already prepopulated, as given in the problem statement.Output format :The result of the query will be the seller ID(s) who achieved the highest total sales based on the cumulative sum of prices for all their sales as shown below.seller_id13
Question
Problem StatementWrite a query to retrieve the seller ID(s) who made the highest total sales based on the total sum of prices for all their sales.Table: Productproduct_id is the primary key of this table. Each row of this table indicates the name and the price of each product. Table: SalesThis table has no primary key, it can have repeated rows. product_id is a foreign key to the Product table. Note: All records are prepopulated.Input format :The input tables are already prepopulated, as given in the problem statement.Output format :The result of the query will be the seller ID(s) who achieved the highest total sales based on the cumulative sum of prices for all their sales as shown below.seller_id13
Solution 1
To solve this problem, you would need to write a SQL query that joins the 'Product' and 'Sales' tables on the 'product_id' field. Then, you would group the results by 'seller_id' and sum the 'price' field. Finally, you would order the results by the sum in descending order and limit the results to the top seller. Here is a step-by-step breakdown of the SQL query:
- Join the 'Product' and 'Sales' tables on the 'product_id' field:
SELECT s.seller_id, SUM(p.price) as total_sales
FROM Sales s
JOIN Product p ON s.product_id = p.product_id
- Group the results by 'seller_id' and sum the 'price' field:
GROUP BY s.seller_id
- Order the results by the sum in descending order and limit the results to the top seller:
ORDER BY total_sales DESC
LIMIT 1
So, the complete SQL query would be:
SELECT s.seller_id, SUM(p.price) as total_sales
FROM Sales s
JOIN Product p ON s.product_id = p.product_id
GROUP BY s.seller_id
ORDER BY total_sales DESC
LIMIT 1
This query will return the seller ID who made the highest total sales based on the total sum of prices for all their sales.
Solution 2
To solve this problem, you would need to write a SQL query that joins the 'Product' and 'Sales' tables on the 'product_id' field. Then, you would group the results by 'seller_id' and sum the 'price' field. Finally, you would order the results by the total sales in descending order and limit the results to the top seller. Here is a step-by-step breakdown of the SQL query:
- Join the 'Product' and 'Sales' tables on the 'product_id' field:
SELECT s.seller_id, SUM(p.price) as total_sales
FROM Sales s
JOIN Product p ON s.product_id = p.product_id
- Group the results by 'seller_id' and sum the 'price' field:
GROUP BY s.seller_id
- Order the results by the total sales in descending order:
ORDER BY total_sales DESC
- Limit the results to the top seller:
LIMIT 1
So, the complete SQL query would be:
SELECT s.seller_id, SUM(p.price) as total_sales
FROM Sales s
JOIN Product p ON s.product_id = p.product_id
GROUP BY s.seller_id
ORDER BY total_sales DESC
LIMIT 1
This query will return the seller ID who made the highest total sales based on the total sum of prices for all their sales.
Similar Questions
Write a query to retrieve the seller ID(s) who made the highest total sales based on the total sum of prices for all their sales.Table: Productproduct_id is the primary key of this table. Each row of this table indicates the name and the price of each product. Table: SalesThis table has no primary key, it can have repeated rows. product_id is a foreign key to the Product table.
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