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The sum of ages of 5 children born at intervals of 3 years each, is 50 years. What is the age of the youngest child?

Question

The sum of ages of 5 children born at intervals of 3 years each, is 50 years. What is the age of the youngest child?

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Solution

Let's denote the age of the youngest child as x.

Since the children are born at intervals of 3 years each, the ages of the children can be represented as x, x+3, x+6, x+9, and x+12.

According to the problem, the sum of their ages is 50. So, we can write the equation:

x + (x+3) + (x+6) + (x+9) + (x+12) = 50

Solving this equation will give us the age of the youngest child.

First, simplify the left side of the equation:

5x + 30 = 50

Then, subtract 30 from both sides of the equation:

5x = 20

Finally, divide both sides of the equation by 5:

x = 4

So, the age of the youngest child is 4 years.

This problem has been solved

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