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In a Young's double slit experiment the separation of the slits is 0.23 mm. The wavelength of the light is 558 nm. Determine the angle at which the third dark fringe out from the centre occurs. Give your answer as a positive value

Question

In a Young's double slit experiment the separation of the slits is 0.23 mm. The wavelength of the light is 558 nm. Determine the angle at which the third dark fringe out from the centre occurs. Give your answer as a positive value

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Solution

Sure, here's how you can calculate the angle for the third dark fringe in a Young's double slit experiment:

  1. First, we need to understand the formula for the position of dark fringes in a Young's double slit experiment. The formula is: sinθ = mλ / d, where m is the order of the dark fringe, λ is the wavelength of the light, and d is the separation of the slits.

  2. In this case, we are looking for the third dark fringe, so m = 3. The wavelength of the light (λ) is given as 558 nm, which is 558 x 10^-9 m. The separation of the slits (d) is given as 0.23 mm, which is 0.23 x 10^-3 m.

  3. Substituting these values into the formula, we get: sinθ = (3 * 558 x 10^-9 m) / (0.23 x 10^-3 m)

  4. To find the angle θ, we need to take the inverse sine (sin^-1) of the result.

  5. So, θ = sin^-1[(3 * 558 x 10^-9 m) / (0.23 x 10^-3 m)]

  6. Calculate the above expression to get the value of θ. This will give you the angle at which the third dark fringe occurs.

Remember to convert the result from radians to degrees if your calculator is set to give the answer in radians.

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