Given an array of integers A, every element appears twice except for one. Find that single one.NOTE: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?Problem Constraints1 <= |A| <= 20000000 <= A[i] <= INTMAXInput FormatFirst and only argument of input contains an integer array A.Output FormatReturn a single integer denoting the single element.Example InputInput 1: A = [1, 2, 2, 3, 1]Input 2: A = [1, 2, 2]Example OutputOutput 1: 3Output 2: 1Example ExplanationExplanation 1:3 occurs once.Explanation 2:1 occurs once.
Question
Given an array of integers A, every element appears twice except for one. Find that single one.NOTE: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?Problem Constraints1 <= |A| <= 20000000 <= A[i] <= INTMAXInput FormatFirst and only argument of input contains an integer array A.Output FormatReturn a single integer denoting the single element.Example InputInput 1: A = [1, 2, 2, 3, 1]Input 2: A = [1, 2, 2]Example OutputOutput 1: 3Output 2: 1Example ExplanationExplanation 1:3 occurs once.Explanation 2:1 occurs once.
Solution
This problem can be solved using the XOR operation. The XOR of all elements in the array will give us the number that appears only once. This is because the XOR of two same numbers is 0 and the XOR of a number with 0 is the number itself.
Here is a Python solution:
def singleNumber(A):
result = 0
for num in A:
result ^= num
return result
This function iterates over each number in the array, performing an XOR operation with the current result. At the end of the iteration, the result will be the number that appears only once in the array.
This solution has a linear runtime complexity as it only needs to iterate over the array once. It also does not use extra memory as it only uses a single variable to store the result.
Similar Questions
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