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If h is the function given by ℎ(𝑥)=(𝑓∘𝑔)(𝑥)h(x)=(f∘g)(x), where f(x) = 5x2 - 1 and g(x) = |x|, then h(x) =A.5|x| - 1B.5x - 1C.|5x2 - 1|D.5x2 - |x|E.5|x|2 - 1SUBMITarrow_backPREVIOUS

Question

If h is the function given by ℎ(𝑥)=(𝑓∘𝑔)(𝑥)h(x)=(f∘g)(x), where f(x) = 5x2 - 1 and g(x) = |x|, then h(x) =A.5|x| - 1B.5x - 1C.|5x2 - 1|D.5x2 - |x|E.5|x|2 - 1SUBMITarrow_backPREVIOUS

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Solution

Para resolver la función h(x)=(fg)(x) h(x) = (f \circ g)(x) , primero necesitamos entender qué significa la notación de composición de funciones (fg)(x) (f \circ g)(x) . Esto se traduce a f(g(x)) f(g(x)) .

Dado que f(x)=5x21 f(x) = 5x^2 - 1 y g(x)=x g(x) = |x| , primero evaluamos g(x) g(x) :

g(x)=x g(x) = |x|

Luego, sustituimos g(x) g(x) en f(x) f(x) :

f(g(x))=f(x) f(g(x)) = f(|x|)

Ahora, sustituimos x |x| en la función f f :

f(x)=5(x)21 f(|x|) = 5(|x|)^2 - 1

Dado que (x)2=x2 (|x|)^2 = x^2 , tenemos:

f(x)=5x21 f(|x|) = 5x^2 - 1

Por lo tanto, la función h(x) h(x) es:

h(x)=5x21 h(x) = 5x^2 - 1

La respuesta correcta es:

E.5x21 E. 5|x|^2 - 1

This problem has been solved

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