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A boy throws a ball up into the air with a speed of 12.3 m/s. The ball has a mass of 0.25 kg. How much gravitational potential energy will the ball have at the top of its flight? (Assume there is no air resistance.)A.12.1 JB.18.9 JC.13.5 JD.20.2 J

Question

A boy throws a ball up into the air with a speed of 12.3 m/s. The ball has a mass of 0.25 kg. How much gravitational potential energy will the ball have at the top of its flight? (Assume there is no air resistance.)A.12.1 JB.18.9 JC.13.5 JD.20.2 J

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Solution

To solve this problem, we need to use the formula for gravitational potential energy, which is:

Potential Energy (PE) = mass (m) * gravity (g) * height (h)

We know the mass (m) is 0.25 kg and the acceleration due to gravity (g) is approximately 9.8 m/s². However, we don't know the height (h) the ball reaches.

We can find the height by using the formula for the maximum height reached by a projectile, which is:

h = (initial velocity²) / (2*g)

The initial velocity is given as 12.3 m/s. So, we substitute these values into the formula:

h = (12.3 m/s)² / (2*9.8 m/s²) = 7.74 m

Now we can find the potential energy at the top of the flight by substituting the values of m, g, and h into the potential energy formula:

PE = 0.25 kg * 9.8 m/s² * 7.74 m = 18.9 J

So, the ball will have 18.9 Joules of gravitational potential energy at the top of its flight. The correct answer is B. 18.9 J.

This problem has been solved

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