A pendulum is made by attaching a 4.00 kg mass to the end of a thin, massless rod. The period of small-amplitude oscillations of the pendulum is 1.00 sec. What is the length of the rod?
Question
A pendulum is made by attaching a 4.00 kg mass to the end of a thin, massless rod. The period of small-amplitude oscillations of the pendulum is 1.00 sec. What is the length of the rod?
Solution
The period of a simple pendulum is given by the formula:
T = 2π √(L/g)
where: T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
We can rearrange this formula to solve for L:
L = (T^2 * g) / (4π^2)
Given that T = 1.00 sec and g = 9.81 m/s^2 (approximate value of acceleration due to gravity on Earth), we can substitute these values into the formula:
L = (1.00 sec^2 * 9.81 m/s^2) / (4π^2)
L = 0.248 m
So, the length of the rod is approximately 0.248 meters.
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