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Find the equation of a line parallel tominus, 3, x, plus, y, equals, minus, 5−3x+y=−5that passes through the point left bracket, minus, 7, comma, 7, right bracket(−7,7).

Question

Find the equation of a line parallel tominus, 3, x, plus, y, equals, minus, 5−3x+y=−5that passes through the point left bracket, minus, 7, comma, 7, right bracket(−7,7).

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Solution

The equation of a line in the slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

The given line is -3x + y = -5. We can rewrite this in slope-intercept form by isolating y:

y = 3x - 5

The slope of this line is 3. Since parallel lines have the same slope, the line we're looking for also has a slope of 3.

Now we know that the equation of the line we're looking for is of the form y = 3x + b. We can find b by substituting the coordinates of the given point into this equation:

7 = 3*(-7) + b 7 = -21 + b b = 7 + 21 b = 28

So, the equation of the line parallel to -3x + y = -5 that passes through the point (-7,7) is y = 3x + 28.

This problem has been solved

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