Three particles,each having a charge of 10µc and are placed at the vertices of an equilateral triangle of side 10cm.Find the work done by a person in pulling them apart to infinite separation

Sure, here is the step by step solution:

Step 1: Identify the given values Charge of each particle, q = 10 µC = 10 * 10^-6 C Distance between each particle, r = 10 cm = 10 * 10^-2 m

Step 2: Calculate the force between two charges The force between two charges is given by Coulomb's law: F = k * q1 * q2 / r^2 Where k is Coulomb's constant, k = 9 * 10^9 N m^2/C^2

Substituting the given values: F = 9 * 10^9 * (10 * 10^-6)^2 / (10 * 10^-2)^2 F = 9 N

Step 3: Calculate the work done to move a charge to infinity The work done to move a charge to infinity is equal to the potential energy of the system, which is given by: W = k * q1 * q2 / r

Substituting the given values: W = 9 * 10^9 * (10 * 10^-6)^2 / (10 * 10^-2) W = 9 J

Step 4: Calculate the total work done Since there are three charges, the total work done is three times the work done to move one charge to infinity: W_total = 3 * W W_total = 3 * 9 J W_total = 27 J

So, the work done by a person in pulling them apart to infinite separation is 27 Joules.