To solve this problem, we first need to find out how much of the tank each tap can fill in one hour.

1. Tap A can fill the tank in 12 hours, so in one hour it fills 1/12 of the tank.
2. Tap B can fill the tank in 15 hours, so in one hour it fills 1/15 of the tank.
3. Tap C can fill the tank in 20 hours, so in one hour it fills 1/20 of the tank.

Next, we need to figure out how much of the tank is filled in the first two hours. In the first hour, taps A and B are open, so they fill 1/12 + 1/15 of the tank. In the second hour, taps A and C are open, so they fill 1/12 + 1/20 of the tank.

Adding these two together, we find that in two hours, the taps fill (1/12 + 1/15) + (1/12 + 1/20) = 5/60 + 4/60 + 5/60 + 3/60 = 17/60 of the tank.

Since this is the amount filled in two hours, we can find out how long it takes to fill the tank by dividing the total tank volume (1) by the amount filled in two hours (17/60), and then multiplying by 2 to convert from "tank per 2 hours" to "hours per tank".

This gives us (1 / (17/60)) * 2 = 7.06 hours.

So, the tank will be full in approximately 7 hours. Therefore, the answer is (b) 7 hrs.

Question

To solve this problem, we first need to find out how much of the tank each tap can fill in one hour.

1. Tap A can fill the tank in 12 hours, so in one hour it fills 1/12 of the tank.
2. Tap B can fill the tank in 15 hours, so in one hour it fills 1/15 of the tank.
3. Tap C can fill the tank in 20 hours, so in one hour it fills 1/20 of the tank.

Next, we need to figure out how much of the tank is filled in the first two hours. In the first hour, taps A and B are open, so they fill 1/12 + 1/15 of the tank. In the second hour, taps A and C are open, so they fill 1/12 + 1/20 of the tank.

Adding these two together, we find that in two hours, the taps fill (1/12 + 1/15) + (1/12 + 1/20) = 5/60 + 4/60 + 5/60 + 3/60 = 17/60 of the tank.

Since this is the amount filled in two hours, we can find out how long it takes to fill the tank by dividing the total tank volume (1) by the amount filled in two hours (17/60), and then multiplying by 2 to convert from "tank per 2 hours" to "hours per tank".

This gives us (1 / (17/60)) * 2 = 7.06 hours.

So, the tank will be full in approximately 7 hours. Therefore, the answer is (b) 7 hrs.

Knowee AI · Accepted Answer

To solve this problem, we first need to find out how much of the tank each tap can fill in one hour.

1. Tap A can fill the tank in 12 hours, so in one hour it fills 1/12 of the tank.
2. Tap B can fill the tank in 15 hours, so in one hour it fills 1/15 of the tank.
3. Tap C can fill the tank in 20 hours, so in one hour it fills 1/20 of the tank.

Next, we need to figure out how much of the tank is filled in the first two hours. In the first hour, taps A and B are open, so they fill 1/12 + 1/15 of the tank. In the second hour, taps A and C are open, so they fill 1/12 + 1/20 of the tank.

Adding these two together, we find that in two hours, the taps fill (1/12 + 1/15) + (1/12 + 1/20) = 5/60 + 4/60 + 5/60 + 3/60 = 17/60 of the tank.

Since this is the amount filled in two hours, we can find out how long it takes to fill the tank by dividing the total tank volume (1) by the amount filled in two hours (17/60), and then multiplying by 2 to convert from "tank per 2 hours" to "hours per tank".

This gives us (1 / (17/60)) * 2 = 7.06 hours.

So, the tank will be full in approximately 7 hours. Therefore, the answer is (b) 7 hrs.

Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternatively, the tank will be full in :Select one:a. 6 hrsb. 7 hrsc. 6.5 hrsd. 7.5 hrs

Question

Solution

Similar Questions

Upgrade your grade with Knowee