The question seems to be referring to a standard six-sided die. The numbers on a standard die are 1, 2, 3, 4, 5, and 6.

The numbers that are divisible by 3 on a die are 3 and 6.

So, there are 2 favorable outcomes (3 and 6).

The total number of possible outcomes is 6 (since a die has 6 faces).

The probability of an event is given by the ratio of the number of favorable outcomes to the number of possible outcomes.

So, the probability that the number on the upward face is divisible by 3 is 2/6 = 1/3.

Question

The question seems to be referring to a standard six-sided die. The numbers on a standard die are 1, 2, 3, 4, 5, and 6.

The numbers that are divisible by 3 on a die are 3 and 6.

So, there are 2 favorable outcomes (3 and 6).

The total number of possible outcomes is 6 (since a die has 6 faces).

The probability of an event is given by the ratio of the number of favorable outcomes to the number of possible outcomes.

So, the probability that the number on the upward face is divisible by 3 is 2/6 = 1/3.

Knowee AI · Accepted Answer

The question seems to be referring to a standard six-sided die. The numbers on a standard die are 1, 2, 3, 4, 5, and 6.

The numbers that are divisible by 3 on a die are 3 and 6.

So, there are 2 favorable outcomes (3 and 6).

The total number of possible outcomes is 6 (since a die has 6 faces).

The probability of an event is given by the ratio of the number of favorable outcomes to the number of possible outcomes.

So, the probability that the number on the upward face is divisible by 3 is 2/6 = 1/3.

Find the probability that the number on the upward face is divisible by 3. (Enter the probability as a fraction.)