Roll two fair dice separately. Each dice has six faces. Let B be the event that the sum of the two rolls is at most seven. P(B) = _____________.Question 5Answera.36/21b.6/21c.21/36
Question
Roll two fair dice separately. Each dice has six faces. Let B be the event that the sum of the two rolls is at most seven. P(B) = _____________.Question 5Answera.36/21b.6/21c.21/36
Solution
To solve this problem, we first need to understand the total number of possible outcomes when rolling two dice. Since each die has 6 faces, the total number of outcomes is 6*6 = 36.
Next, we need to find out the number of outcomes where the sum of the two rolls is at most seven. These are:
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (3,1), (3,2), (3,3), (3,4), (4,1), (4,2), (4,3), (5,1), (5,2), (6,1)
Counting these pairs, we find there are 21 such outcomes.
Therefore, the probability P(B) that the sum of the two rolls is at most seven is 21/36, which simplifies to 7/12.
So, the answer is not given in the options you provided. The correct answer is 7/12.
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