If the reaction 2A+B->2D is an elementary reaction and the rate of this reaction is R for certain concentrations of A and B, what will be the rate of the reaction if those concentrations are doubled? A) 2R B) 4R C) 8R D) 4R2 E) R2
Question
If the reaction 2A+B->2D is an elementary reaction and the rate of this reaction is R for certain concentrations of A and B, what will be the rate of the reaction if those concentrations are doubled?
A) 2R B) 4R C) 8R D) 4R2 E) R2
Solution
The rate law for an elementary reaction is directly derived from its stoichiometry. For the given elementary reaction, the rate law can be written as:
Rate = k[A]^2[B]
where k is the rate constant, [A] is the concentration of A, and [B] is the concentration of B.
If the concentrations of A and B are both doubled, the new rate (R') will be:
R' = k[2A]^2[2B] = 4k[A]^2 * 2k[B] = 8k[A]^2[B] = 8R
So, the rate of the reaction will be eight times the original rate if the concentrations of A and B are both doubled. Therefore, the correct answer is C) 8R.
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