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A bridge hand is found by taking 13 cards at random and without replacementfrom a deck of 52 playing cards. Find the probability of drawing each of the following hands.(a) One in which there are 5 spades, 4 hearts, 3 diamonds, and 1 club.(b) One in which there are 5 spades, 4 hearts, 2 diamonds, and 2 clubs(c) One in which there are 5 spades, 4 hearts, 1 diamond, and 3 clubs.

Question

A bridge hand is found by taking 13 cards at random and without replacementfrom a deck of 52 playing cards. Find the probability of drawing each of the following hands.(a) One in which there are 5 spades, 4 hearts, 3 diamonds, and 1 club.(b) One in which there are 5 spades, 4 hearts, 2 diamonds, and 2 clubs(c) One in which there are 5 spades, 4 hearts, 1 diamond, and 3 clubs.

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Solution

Sure, I can do that. Here are the solutions:

(a) In a deck of 52 cards, there are 13 cards of each suit. The probability of drawing 5 spades, 4 hearts, 3 diamonds, and 1 club is given by:

(13 choose 5) * (13 choose 4) * (13 choose 3) * (13 choose 1) / (52 choose 13)

This simplifies to:

(1287 * 715 * 286 * 13) / 635013559600 = 0.000398

(b) The probability of drawing 5 spades, 4 hearts, 2 diamonds, and 2 clubs is given by:

(13 choose 5) * (13 choose 4) * (13 choose 2) * (13 choose 2) / (52 choose 13)

This simplifies to:

(1287 * 715 * 78 * 78) / 635013559600 = 0.000265

(c) The probability of drawing 5 spades, 4 hearts, 1 diamond, and 3 clubs is given by:

(13 choose 5) * (13 choose 4) * (13 choose 1) * (13 choose 3) / (52 choose 13)

This simplifies to:

(1287 * 715 * 13 * 286) / 635013559600 = 0.000398

So, the probabilities are approximately 0.000398, 0.000265, and 0.000398, respectively.

This problem has been solved

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