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Fill in the blank in the function below so that the function prints the integers from 0 up to the integer value it was given for N. That is, if the function is executed with the value of N being 6, it should print 0, 1, 2, 3, 4, 5, 6.def print_integer(N):    if (_________):        print_integer(N - 1)        print(N)

Question

Fill in the blank in the function below so that the function prints the integers from 0 up to the integer value it was given for N. That is, if the function is executed with the value of N being 6, it should print 0, 1, 2, 3, 4, 5, 6.def print_integer(N):    if (_________):        print_integer(N - 1)        print(N)

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Solution

The blank in the function should be filled with "N >= 0". This condition checks if N is greater than or equal to 0. If it is, the function calls itself with the argument N - 1, and then prints N. This results in the numbers from 0 to N being printed in ascending order. Here is the completed function:

def print_integer(N): 
    if (N >= 0): 
        print_integer(N - 1) 
        print(N)

This function uses recursion to print the numbers. The base case for the recursion is when N is less than 0, at which point the function stops calling itself.

This problem has been solved

Similar Questions

Fill in the blank in the function below so that the function prints the integers from 0 up to the integer value it was given for N. That is, if the function is executed with the value of N being 5, it should print 0, 1, 2, 3, 4, 5.def xxx(N):    if (_________):        xxx(N - 1)        print(N)

Fill in the blank in the function below so that the function prints the integers from 1 down to the integer value it was given for N. That is, if the function is executed with the value of N being -3, it should print 1, 0, -1, -2, -3.def xxx(N):    if (_________):        xxx(N + 1)        print(N)

What sequence of numbers would be printed if the following function were executed with the value of N being 1?def print_sequence(N):    while (N < 6):        print(N)        N = N + 2    print(N)

____________ will be the output of the following python programN = 6while N <= 6:    if N < 6:        N = N + 1    print(N)

def print_n(s, n):     if n > 0:          print(s)          print_n(s, n-1)     return nn = 3while print_n("hi", n):     print_n("there!", n)     n = 0

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