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If two populations are independent and each normally distributed and the population standard deviations are not equal, the test statisticT=X¯1−X¯2−(μ1−μ2)S21n1+S22n2‾‾‾‾‾‾‾‾√𝑇=𝑋¯1−𝑋¯2−(𝜇1−𝜇2)𝑆12𝑛1+𝑆22𝑛2 follows a:Question 4Select one:a.t-distribution with n1+n2−2 degrees of freedomt-distribution with 𝑛1+𝑛2−2 degrees of freedom b.standard normal distribution with n1+n2−2 degrees of freedomstandard normal distribution with 𝑛1+𝑛2−2 degrees of freedom c.t-distribution with degrees of freedom equal to (S21n1+S22n2)2(S21/n1)2n1−1+(S22/n2)2n2−1t-distribution with degrees of freedom equal to (𝑆12𝑛1+𝑆22𝑛2)2(𝑆12/𝑛1)2𝑛1−1+(𝑆22/𝑛2)2𝑛2−1 d.t-distribution with n−1 degrees of freedom

Question

If two populations are independent and each normally distributed and the population standard deviations are not equal, the test statisticT=X¯1−X¯2−(μ1−μ2)S21n1+S22n2‾‾‾‾‾‾‾‾√𝑇=𝑋¯1−𝑋¯2−(𝜇1−𝜇2)𝑆12𝑛1+𝑆22𝑛2 follows a:Question 4Select one:a.t-distribution with n1+n2−2 degrees of freedomt-distribution with 𝑛1+𝑛2−2 degrees of freedom b.standard normal distribution with n1+n2−2 degrees of freedomstandard normal distribution with 𝑛1+𝑛2−2 degrees of freedom c.t-distribution with degrees of freedom equal to (S21n1+S22n2)2(S21/n1)2n1−1+(S22/n2)2n2−1t-distribution with degrees of freedom equal to (𝑆12𝑛1+𝑆22𝑛2)2(𝑆12/𝑛1)2𝑛1−1+(𝑆22/𝑛2)2𝑛2−1 d.t-distribution with n−1 degrees of freedom

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Solution

The correct answer is c. t-distribution with degrees of freedom equal to (𝑆12𝑛1+𝑆22𝑛2)2(𝑆12/𝑛1)2𝑛1−1+(𝑆22/𝑛2)2𝑛2−1. This is because when the population standard deviations are not equal, the degrees of freedom for the t-distribution are calculated using the formula provided in option c. This formula is known as the Welch-Satterthwaite equation.

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