Consider the PDA with only transitions (q0, a, e) -> (q0, e) for each symbol a in the input alphabet. q0 is an accepting state. i.e., from the initial state, it consumes one input symbol, does no stack operations and stays in the same state. What is the language decided by this PDA?1 pointEmpty set{ e }Sigma*This is an invalid PDA.
Question
Consider the PDA with only transitions (q0, a, e) -> (q0, e) for each symbol a in the input alphabet. q0 is an accepting state. i.e., from the initial state, it consumes one input symbol, does no stack operations and stays in the same state. What is the language decided by this PDA?1 pointEmpty set{ e }Sigma*This is an invalid PDA.
Solution
The language decided by this PDA is Sigma*. This is because the PDA consumes one input symbol and stays in the same state without any stack operations. It does not matter what the input symbol is, the PDA will always accept it. Therefore, it accepts all possible strings, including the empty string, over the input alphabet.
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