To find the length of the third side of the triangle, we can use the Law of Cosines. The Law of Cosines states that c² = a² + b² - 2abcos(C), where a and b are the lengths of the two sides of the triangle, C is the angle between them, and c is the length of the side opposite angle C.

Here, a = 2, b = 5, and C = 60°.

So, c² = 2² + 5² - 2*2*5*cos(60°)

= c² = 4 + 25 - 20*0.5 (since cos(60°) = 0.5)

= c² = 29 - 10

= c² = 19

Taking the square root of both sides to solve for c, we get c = √19.

So, the length of the third side of the triangle is √19 units.

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To find the length of the third side of the triangle, we can use the Law of Cosines. The Law of Cosines states that c² = a² + b² - 2abcos(C), where a and b are the lengths of the two sides of the triangle, C is the angle between them, and c is the length of the side opposite angle C.

Here, a = 2, b = 5, and C = 60°.

So, c² = 2² + 5² - 2*2*5*cos(60°)

=> c² = 4 + 25 - 20*0.5 (since cos(60°) = 0.5)

=> c² = 29 - 10

=> c² = 19

Taking the square root of both sides to solve for c, we get c = √19.

So, the length of the third side of the triangle is √19 units.

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To find the length of the third side of the triangle, we can use the Law of Cosines. The Law of Cosines states that c² = a² + b² - 2abcos(C), where a and b are the lengths of the two sides of the triangle, C is the angle between them, and c is the length of the side opposite angle C.

Here, a = 2, b = 5, and C = 60°.

So, c² = 2² + 5² - 2*2*5*cos(60°)

=> c² = 4 + 25 - 20*0.5 (since cos(60°) = 0.5)

=> c² = 29 - 10

=> c² = 19

Taking the square root of both sides to solve for c, we get c = √19.

So, the length of the third side of the triangle is √19 units.

Suppose a triangle has two sides of length 2 and 5 and that the angle between these two sides is 60°. What is the length of the third side of the triangle?A.2B.C.5D.

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