Let's say we are performing a binary search on the list [3, 7, 8, 11, 23, 48, 52, 65] to look for the number 8. What numbers would 8 be compared to determine it is in the list?Question 29Select one:65, 23, 8cross out3, 7, 8cross out23, 8cross out11, 7, 8

Binary search is an efficient algorithm for finding an item from a sorted list of items. It works by repeatedly dividing in half the portion of the list that could contain the item, until you've narrowed down the possible locations to just one.

Here's how we would use binary search to look for the number 8 in the list [3, 7, 8, 11, 23, 48, 52, 65]:

1. First, we would compare 8 with the middle element in the list. The middle element is 23. Since 8 is less than 23, we know that if 8 is in the list, it must be in the first half of the list.

2. So, we repeat the process with the first half of the list: [3, 7, 8, 11]. Again, we compare 8 with the middle element. This time, the middle element is 7. Since 8 is greater than 7, we know that if 8 is in the list, it must be in the second half of this new list.

3. We repeat the process again with the second half of the new list: [8, 11]. We compare 8 with the middle element. The middle element is 8, which is exactly what we're looking for. So, we've found 8 in the list.

So, the numbers that 8 would be compared to in this binary search are 23, 7, and 8.