Find the derivative of g(x)=∫x−2t2+1−−−−−√dt
Question
Find the derivative of g(x)=∫x−2t2+1−−−−−√dt
Solution
The function you've given is a definite integral with a variable upper limit. To find the derivative of this function, we can use the Fundamental Theorem of Calculus Part 1, which states that if a function g(x) is defined as an integral from a constant to x,
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