Find the magnitude of the orbital magnetic dipole moment of the electron in in the 3p state. Provide your answer in terms of the number of Bohr magneton.
Question
Find the magnitude of the orbital magnetic dipole moment of the electron in in the 3p state. Provide your answer in terms of the number of Bohr magneton.
Solution
The orbital magnetic dipole moment (μL) of an electron in an atomic orbital is given by the formula:
μL = -μB * L
where μB is the Bohr magneton and L is the orbital angular momentum quantum number.
For a 3p state, the value of L is 1 (since p corresponds to l=1).
So, the magnitude of the orbital magnetic dipole moment of the electron in the 3p state is:
μL = -μB * 1 = -μB
Therefore, the magnitude of the orbital magnetic dipole moment of the electron in the 3p state is 1 Bohr magneton.
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