f, of, x, equals, start fraction, 2, x, plus, 9, divided by, 2, x, minus, 7, end fractionf(x)= 2x−72x+9
Question
f, of, x, equals, start fraction, 2, x, plus, 9, divided by, 2, x, minus, 7, end fractionf(x)= 2x−72x+9
Solution
It seems like there's a bit of confusion in your question. The function you've written seems to be in two different formats. If the function is (2x + 9) / (2x - 7), then it's already in its simplest form. If you want to find the value of the function for a specific value of x, you can substitute that value in place of x. If you want to do something else with the function, please provide more details.
Similar Questions
For the function f, of, x, equals, start fraction, 2, x, plus, 9, divided by, 2, x, minus, 7, end fractionf(x)= 2x−72x+9 , find f, to the power minus 1 , left bracket, x, right bracketf −1 (x).
f(x)=7(x+2)2–3.
Given f, of, x, equals, minus, 2, x, squared, minus, 4, x, plus, 13f(x)=−2x 2 −4x+13, find f, of, minus, 7f(−7)
What is (f–g)(x)?f(x)=2x2–7xg(x)=x2–xWrite your answer as a polynomial or a rational function in simplest form.
2x−72x+9 , find f, to the power minus 1 , left bracket, x, right bracketf −1 (x).AnswerAttempt 3 out of 8
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