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cos2 ๐œƒ1+sin ๐œƒ = 1 โˆ’ sin ๐œƒ

Question

cos2 ๐œƒ1+sin ๐œƒ = 1 โˆ’ sin ๐œƒ

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Solution

The given equation is cos^2 ๐œƒ + sin ๐œƒ = 1 - sin ๐œƒ.

Step 1: We know that cos^2 ๐œƒ = 1 - sin^2 ๐œƒ (from the Pythagorean identity in trigonometry). So, we can replace cos^2 ๐œƒ in the equation.

So, the equation becomes 1 - sin^2 ๐œƒ + sin ๐œƒ = 1 - sin ๐œƒ.

Step 2: Simplify the equation by subtracting sin ๐œƒ from both sides.

This gives us 1 - sin^2 ๐œƒ = 1 - 2sin ๐œƒ.

Step 3: Rearrange the equation to make it a quadratic equation in terms of sin ๐œƒ.

This gives us sin^2 ๐œƒ + 2sin ๐œƒ - 1 = 0.

Step 4: Solve this quadratic equation to find the values of sin ๐œƒ.

This can be done either by factoring, completing the square, or using the quadratic formula. The solutions will give you the possible values of ๐œƒ.

This problem has been solved

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