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From the given following which of these operators have the highest order of precedence.Options+' and '-'(' and ')'*' and '/'~' and '^'

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From the given following which of these operators have the highest order of precedence.Options+' and '-'(' and ')'*' and '/'~' and '^'

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Solution

The operators with the highest order of precedence from the given options are '(' and ')'. In most programming languages, operations within parentheses are performed first. This is followed by the unary operators '~' (bitwise NOT) and '-' (negation), then the multiplicative operators '*' and '/', and finally the additive operators '+' and '-'. The '^' operator (usually representing exponentiation or bitwise XOR depending on the language) can vary in its position in this order. However, it's important to note that the exact order can depend on the specific programming language being used.

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